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Loop Programs based on Mathematical Series

/ Programming Questions

Question 1

WAP to input a number n and print the first n terms of the following series 2,5,8,11,14,17,….uptil n terms For example: If the value of n = 5, then your program should print out the following 2,5,8,11,14 (n = 5 terms)

java 

        
            
import java.util.*;
public class Test
{
    public static void main()
    {
    int n, i, x;
    Scanner sc = new Scanner(System.in);

    System.out.println("enter the number");
    n = sc.nextInt();

    for (i = 1; i <= n; i++)
    {
        x = (3 * i) - 1;
        System.out.println(x);
    }
    }
}

python 

        
            
n = int(input("Enter a number: "))
for i in range(1,n + 1):
    x = (3 * i) - 1
    print(x)

Question 2

WAP to print out the following series 1, 2, 4, 7, 11, 16, 22, 29 .. uptil n terms where n is taken as an input by the program

java 

        
            
import java.util.*;
public class Test
{
    public static void main()
    {
    int a = 1, n, i;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the number of terms");
    n = sc.nextInt();
    
    for (i = 1; i <= n; i++)
    {
        System.out.println(a);
        a += i;
    }
    }
}

python 

        
            
n = int(input('Enter the number of terms: '))
a = 1

for i in range(1, n+1, 1):
    print(a)
    a += i

Question 3

WAP to take 2 inputs from the user - x and n. Then print out the following series x, x2, x3, x4, x5 + …. uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double x, n, i, a;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    System.out.println("Enter the value of x");
    x = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a = Math.pow(x, i);
        System.out.println(a);
    }
    }
}

python 

        
            
n = int(input('Enter the value of n: '))
x = int(input('Enter the value of x: '))

for i in range(1, n+1, 1):
    a = x**i
    print(a)

Question 4

WAP to print out and find the sum of the following series uptil n terms where n comes in as an input from the user 1! + 2! + 3! + 4! + 5! + …. uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, a = 1, s = 0;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a *= i;
        System.out.println(a);
        s += a;
    }
    
    System.out.println("Sum of the series = " + s);
    }
}

python 

        
            
n = int(input('Enter the value of n: '))
a = 1
s = 0

for i in range(1, n+1, 1):
    a *= i
    print(a)
    s += a

print('Sum of the series =', s)

Question 5

WAP to print out the following series uptil n terms where n comes in as an input from the user 1, 2, 9, 64, 625, … uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, a;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a = Math.pow(i, i-1);
        System.out.println(a);
    }
    }
}

python 

        
            
n = int(input('Enter the value of n: '))

for i in range(1, n+1, 1):
    a = i ** (i - 1)
    print(a)

Question 6

WAP to print out the following series uptil n terms where n comes in as an input from the user 0, 7, 26, 63 … uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, a;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a = Math.pow(i, 3) - 1;
        System.out.println(a);
    }
    }
}

python 

        
            
n = int(input('Enter the value of n: '))

for i in range(1, n+1, 1):
    a = (i ** 3) - 1
    print(a)

Question 7

WAP to display n terms of square natural number and their sum, where n is an input For example if n = 4 then the program should print out the series 1,4,9,16 and the sum 1+4+9+16 = 30

java 

        
            
import java.util.*;
public class Test
{
    public static void main()
    {
    int n, x, s = 0, i;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter a number");
    n = sc.nextInt();
    
    // loop from 1 to n
    for (i = 1; i <= n; i++)
    {
        x = i * i;
        System.out.println(x);
        s += x;
    }
    
    System.out.println("Sum = " + s);
    }
}

python 

        
            
n = int(input("enter a number: "))
s = 0
for i in range(1, n + 1, 1):
    x = i * i
    s += x
print('sum =', s)

Question 8

WAP to print out the following series 1 + (1/2!) + (1/3!) + (1/4!) + … uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, a = 1, x;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a *= i;
        x = (1/a);
        System.out.println(x);
    }
    }
}

python 

        
            
n = int(input('Enter the value of n: '))
a = 1
for i in range(1, n+1, 1):
    a *= i
    x = (1/a)
    print(x)

Question 9

WAP to print out and also find the sum of the following series 1 +11 + 111 + 1111 + .. uptil n terms where n is taken as an input by the program

java 

        
            
import java.util.*;
public class Test
{
public static void main()
{
int n, i, x = 0, s = 0;
Scanner sc = new Scanner(System.in);

System.out.println("enter the number");
n = sc.nextInt();

for (i = 1; i <= n; i++)
{
    x = (x * 10) + 1;
    System.out.println(x);
    s += x;
}
System.out.println("Sum = " + s);
}
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
x = 0
for i in range(1,n + 1):
    x = (x * 10) + 1
    print(x)
    s += x
print('sum = ', s)

Question 10

WAP to input 2 numbers a and n - then print out and also find the sum of the following series a-a3+a5-a7+a9 … uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, x, p = 1, a, s = 0;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    System.out.println("Enter the value of a");
    a = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        x = Math.pow(a, p);
        System.out.println(x);
        p += 2;
        a *= -1;
        s += x;
    }
    System.out.println("Sum = " + s);
    }
}

python 

        
            
n = int(input('Enter the value of n: '))
a = int(input('Enter the value of a: '))

p = 1
s = 0

for i in range(1, n+1, 1):
    x = a**p
    print(x)
    p += 2
    a *= -1
    s += x

print("sum of the series:", s)

Question 11

WAP to print out and calculate the sum of the following series 1 - 1/2 + 1/3 - 1/4 + 1/5 -… 1/n where n is a positive integer and input by user.

java 

        
            
import java.util.*;
public class Test
{
    public static void main()
    {
        int n ;
        float i, x, s = 0;
        Scanner sc = new Scanner(System.in);

        System.out.println("enter the number");
        n = sc.nextInt();

        for (i = 1; i <= n; i++)
        {
            if (i % 2 == 0)
                x = -(1 / i);
            else
                x = (1 / i);
            System.out.println(x);
            s += x;
        }
        System.out.println("Sum = " + s);
    }
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    if i % 2 == 0:
        x = -(1 / i)
    else:
        x = (1 / i)
    print(x)
    s += x
print('sum = ', s)

Question 12

WAP to take an input n from the user and find the sum of the following series ½ + ¼ + ⅙ + ⅛ + 1/10 + 1/12 + …. + 1/2n The value of n indicates the number of terms. For example, if the input n = 5, then the series will be ½ + ¼ + ⅙ + ⅛ + 1/10 i.e. n = 5 terms

java 

        
            
import java.util.*;
public class Loops
{
    public static void main()
    {
    int n;
    float i, a, s = 0;
    Scanner sc = new Scanner(System.in);
    
    System.out.println("enter the number");
    n = sc.nextInt();
    
    for (i = 1; i<= n; i++)
    {
        a = (1/(2*i));
        s += a;
        System.out.println(a);
    }
    System.out.println("Sum of the numbers = " + s);
    }
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    x = 1/(2*i)
    print(x)
    s += x
print('sum = ', s)

Question 13

WAP to input 2 numbers x and n - and find the sum of the following series
1+(x2/1)-(x3/2)+(x4/3)-(x5/4) … uptil n terms

java 

        
            
import java.util.*;
import java.lang.*;
public class Test
{
    public static void main()
    {
    double n, i, x, a, s = 1;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the value of n");
    n = sc.nextFloat();
    
    System.out.println("Enter the value of x");
    x = sc.nextFloat();
    
    for (i = 1; i <= n; i++)
    {
        a = (( Math.pow(x, i + 1) )/ i);
        
        // alternate terms are -ve
        if (i % 2 == 0)
            a *= -1;
        
        s += x;
    }
    
    System.out.println("Sum of the series: " + s);
    }
}

python 

        
            
n = int(input('Enter the value of n: '))
x = int(input('Enter the value of x: '))

s = 1

for i in range(1, n+1, 1):
    a = (x ** (i + 1))/i

    # alternating terms are even
    if i % 2 == 0:
        a *= -1

    s += x

print("sum of the series:", s)

Question 14

WAP to input a number n and print the first n terms of the following series 0, 3, 8, 15, 24, 35, 48, 63, 80, 99….uptil n terms For example: If the value of n = 4, then your program should print out the following 0,3,8,15 (n = 4 terms)

java 

        
            
import java.util.*;
public class Test
{
public static void main()
{
int n, i, x = 0, s = 0;
Scanner sc = new Scanner(System.in);

System.out.println("enter the number");
n = sc.nextInt();

for (i = 1; i <= n; i++)
{
    x = (i * i) - 1;
    System.out.println(x);
    s += x;
}
System.out.println("Sum = " + s);
}
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    x = (i*i) - 1
    print(x)
    s += x
print('sum = ', s)

Question 15

Take an input n from the user and find out the sum of the following series ½ + ⅔ + ¾ + ⅘ + … till n number of terms For example, if the value of n = 5, then the series will be ½ + ⅔ + ¾+ ⅘ + ⅚ (so, the series will have 5 terms)

java 

        
            
import java.util.*;
public class Loops
{
    public static void main()
    {
    int n;
    float i, a, s = 0;
    Scanner sc = new Scanner(System.in);
    
    System.out.println("enter the number");
    n = sc.nextInt();
    
    for (i = 1; i<= n; i++)
    {
        a = (i/(i + 1));
        s += a;
        System.out.println(a);
    }
    System.out.println("Sum of the numbers = " + s);
    }
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    x = i / (i + 1)
    print(x)
    s += x
print('sum = ', s)

Question 16

Take an input n from the user and find out the sum of the following series 2/1 + 3/2 +4/3 + 5/4 + … till n number of terms For example, if the value of n = 5, then the series will be 2/1 + 3/2 + 4/3+ 5/4 + 6/5 (so, the series will have 5 terms)

java 

        
            
import java.util.*;
public class Test
{
public static void main()
{
    int n;
    float i, a, s = 0;
    Scanner sc = new Scanner(System.in);
    
    System.out.println("enter the number");
    n = sc.nextInt();
    
    for (i = 1; i<= n; i++)
    {
        a = (i + 1)/i;
        s += a;
        System.out.println(a);
    }
    System.out.println("Sum of the numbers = " + s);
}
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    x = (i + 1)/i
    print(x)
    s += x
print('sum = ', s)

Question 17

Take an input n from the user and find the sum of the following series till n terms ⅕ + 1/10 + 1/15 + 1/20 + …. Till n terms. So, for example if the input of n = 6, the series will have 6 terms which are ⅕ + 1/10 + 1/15 + 1/20 + 1/25 + 1/30

java 

        
            
import java.util.*;
public class Loops
{
    public static void main()
    {
    int n;
    float i, a, s = 0;
    Scanner sc = new Scanner(System.in);
    
    System.out.println("enter thember");
    n = sc.nextInt();
    
    for (i = 1; i<= n; i++)
    {
        a = (1/(5*i));
        s += a;
        System.out.println(a);
    }
    System.out.println("Sum of the numbers = " + s);
    }
}

python 

        
            
n = int(input("Enter a number: "))
s = 0
for i in range(1,n + 1):
    x = 1/(5 * i)
    print(x)
    s += x
print('sum = ', s)

Question 18

Take an input n from the user and print out the Fibonacci Series till n terms. This loop_series_title is defined as follows - 1, 1, 2, 3, 5, 8, 13, 21, 34, 55,…(Sum of 2 terms gives the next term)

java 

        
            
import java.util.*;
public class Test
{
    public static void main()
    {
    int a = 1, b = 1, c, n, i;
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter the number of terms");
    n = sc.nextInt();
    
    for (i = 1; i <= n; i++)
    {
        System.out.println(a);
        c = b;
        b = b + a;
        a = c; 
    }
    }
}

python 

        
            
n = int(input('Enter the number of terms: '))

a = 1
b = 1

for i in range(n):
    print(a)
    c = b
    b = b + a
    a = c

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